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|x2 +5x|<6
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cannot solve after this -6<x2+5x<6
spilt it u will get -6<x2+5x and x2+5x<6 now remove the inequality sign and solve the quadratic equation normally
we get 4 zeros -3,-2,1 and -6
yup its true
then u have to see which values are common and those are the required ones
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hmmm i got the right answer it is [-2,0]
and we have to find the common value which both |x+1|<1 and |x2 +5x|<6 satisfies
yes
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