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Mathematics 7 Online
OpenStudy (anonymous):

|x2 +5x|<6

OpenStudy (anonymous):

cannot solve after this -6<x2+5x<6

OpenStudy (anonymous):

spilt it u will get -6<x2+5x and x2+5x<6 now remove the inequality sign and solve the quadratic equation normally

OpenStudy (anonymous):

we get 4 zeros -3,-2,1 and -6

OpenStudy (anonymous):

yup its true

OpenStudy (anonymous):

then u have to see which values are common and those are the required ones

OpenStudy (anonymous):

hmmm i got the right answer it is [-2,0]

OpenStudy (anonymous):

and we have to find the common value which both |x+1|<1 and |x2 +5x|<6 satisfies

OpenStudy (anonymous):

yes

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