Question

Find the equation of the line that has a slope of 1/4 and passes through (8, -3)

Answer 1

use
y-y1=slope(x-x1)
and (x1,y1)=(8,-3)
implies x1=8 and y1=-3

Answer 2

im still lost so what would the answer be?

Answer 3

??

Answer 4

Use the formula for a line with known slope, \(m\), passing through known point \((x_0,y_0)\):

\[y-y_0 = m(x-x_0)\]

You know \(m = \frac{1}{4}\) and \((x_0,y_0)\) is \((8,-3)\)

Plug in the values to get your line equation. Be careful about subtracting negative numbers...

Answer 5

y+3=(1/4)*(x-8)

Answer 6

\[y+3=\frac{ 1 }{ 4}(x-8)\]

Answer 7

yes

Answer 8

thanks

Answer 9

Might want to rearrange it into slope-intercept form: \(y = mx + b\) but you do have a valid equation for that line, as you can see from the plot here:

Answer 10

say thanks to @whpalmer4 also

Answer 11

I figured it was a thanks to the group :-)

Answer 12

it was for both of you guys :)

Answer 13

Happy to be of some help! But now it's time to hit the sack for me...