Question

.Find the distance between the given points: (4√15, -3√10) (2√15, 8√10)

Answer 1

Given the two points \((x_1, y_1)\) and \((x_2, y_2)\), the distance between these points is given by the formula:
\[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
Substitute and solve.

Answer 2

im having trouble with the radicals could u solve this for?

Answer 3

\[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ d=\sqrt{(2\sqrt{15}-4\sqrt{15})^2+(8\sqrt{10}-(-3\sqrt{10}))^2} \\ \\ d=\sqrt{(-2\sqrt{15})^2+(11\sqrt{10})^2} \\ \\ d=\sqrt{(4(15))+(121(10))} \]

Answer 4

Note:
\(m\sqrt{x}+n\sqrt{x}=(m+n)\sqrt{x}\)

Answer 5

so what would the answer be?

Answer 6

Just finish up the solving part

Answer 7

ok thanks

Answer 8

yw