Question

Two forces F1 and F2 act on a 5.00 kg object. Taking F1=20.0N and F2=15.00N, find the acceleration of the object for the configurations:

a) mass m with F1 acting in the positive x direction and F2 acting perpendicular in the positive y direction

b) mass m with F1 acting in the positive x direction and F2 acting on the object at 60 degrees above the horizontal.

Answer 1

a)
u know the angle between F1 n F2 is 90 degree

Answer 2

the resultant force will b F

Answer 3

so\[F=\sqrt{F _{1}^{2}+F _{2}^{2}+2F _{1}F _{2}\cos 90}\]

Answer 4

\[F=\sqrt{F _{1}^{2}+F _{2}^{2}}\]

Answer 5

\[F=\sqrt{20^{2}+15^{2}}\]

Answer 6

F=25 N

Answer 7

now \[F=ma\]

Answer 8

\[25=5a\]

Answer 9

\[a=5 ms ^{-1}\]

Answer 10

and we can find out the direction of acceleration a