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This one has me pretty stumped too. The numbers I keep getting aren't any of the choices. The average hourly wage of employees of a certain company is $11.14. Assume the variable is normally distributed. If the standard deviation is $3.09, find the probability that a randomly selected employee earns less than $9.44.
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what is the "z score" of 9.44 ? (it will be negative because it is smaller than the average)
@phi would i use the formula data value - mean / standard deviation? I get 9.44 - 11.14 / 3.09 which is -.55
yes. now you need a table that gives you the percent between -inf to -0.55 1 - (-infty to +0.55)
15.8% of $11.14? which is 1.76? @phi
wait that might be wrong
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