2x^2=36
solve by extracting the roots
First what you have to do is get x by itself
so divide by two and im left with x^2=3
36/2 is 3?
18
There you go, now just take the square root of both sides
x=+underoot (18) or - underoot (18)
\[\sqrt{18}=\sqrt{9}*\sqrt{2}\]
Wait... is it (2x)^2 or 2*(x^2) , the first case shall yield x= + or - 3, second ^^
i got 4 for sqroot of 18 but my choices are x=3, x=-3 x=3 3sqroot2 or -3sqroot2
What is the full question.. has the domain of x been mentioned like N (natural numbers)?
solve the equation by extracting the square roots
what is the sqrt9?
3
and 3*sqrt2?
Oh , come on I know the roots! I'm asking about the domain? How can you say it's +3.. it can be -3 as well sqrt(9) shall give both positive and negative ones.
Well the domain is all real numbers since it's a squared
so it would be plus and minus \[3\sqrt{2}\]
ok thanks
Well if it is all real, x can be both positive and negative... if it's natural no, it can be only +3
@Luigi0210 HOw is it 3*sqrt(2)?
\[\sqrt{18}=\sqrt{9}*\sqrt{2}\]
@kittakee : Write the question properly. Is it (2x)^2=36 or 2*(x^2) =36. They'll give different answers.
Bro it's done.. I think
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