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Mathematics 9 Online
OpenStudy (anonymous):

2x^2=36

OpenStudy (anonymous):

solve by extracting the roots

OpenStudy (luigi0210):

First what you have to do is get x by itself

OpenStudy (anonymous):

so divide by two and im left with x^2=3

OpenStudy (luigi0210):

36/2 is 3?

OpenStudy (anonymous):

18

OpenStudy (luigi0210):

There you go, now just take the square root of both sides

OpenStudy (anonymous):

x=+underoot (18) or - underoot (18)

OpenStudy (luigi0210):

\[\sqrt{18}=\sqrt{9}*\sqrt{2}\]

OpenStudy (anonymous):

Wait... is it (2x)^2 or 2*(x^2) , the first case shall yield x= + or - 3, second ^^

OpenStudy (anonymous):

i got 4 for sqroot of 18 but my choices are x=3, x=-3 x=3 3sqroot2 or -3sqroot2

OpenStudy (anonymous):

What is the full question.. has the domain of x been mentioned like N (natural numbers)?

OpenStudy (anonymous):

solve the equation by extracting the square roots

OpenStudy (luigi0210):

what is the sqrt9?

OpenStudy (anonymous):

3

OpenStudy (luigi0210):

and 3*sqrt2?

OpenStudy (anonymous):

Oh , come on I know the roots! I'm asking about the domain? How can you say it's +3.. it can be -3 as well sqrt(9) shall give both positive and negative ones.

OpenStudy (luigi0210):

Well the domain is all real numbers since it's a squared

OpenStudy (luigi0210):

so it would be plus and minus \[3\sqrt{2}\]

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

Well if it is all real, x can be both positive and negative... if it's natural no, it can be only +3

OpenStudy (anonymous):

@Luigi0210 HOw is it 3*sqrt(2)?

OpenStudy (luigi0210):

\[\sqrt{18}=\sqrt{9}*\sqrt{2}\]

OpenStudy (anonymous):

@kittakee : Write the question properly. Is it (2x)^2=36 or 2*(x^2) =36. They'll give different answers.

OpenStudy (luigi0210):

Bro it's done.. I think

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