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Log subscript 4(4x) +log subscript 4(x)= log subscript 4(64) solve for x
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\[\log_{4} 4x+\log_{4}x=\log_{4} 64?\]
yes
log a +log b = log (a*b) apply that from LHS, tell me what you have?
@shaq2341 I guide you only, you have to work. I don't work for you
okay so i got x=4
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how to get this?
since the bases were the same , the formula came down to 4x*x=64
4x^2=64 . Divide by 4 , then x^2=16 which is equal to 4.
thanks for teaching me back, I got the answer from yours , bingo, give you medal for being my tutor. hehehe...
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