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Multiply and show your work. (3 - 2i)(4 + i).
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Is 'i' imaginary?
Btw just distribute them
(a+b)(c+d)=ac+ad+bc+bd
yes the i is imaginary
Then remember that \(i^2 = -1\)
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ohh ok
i need help showing the work i know the answer
Assuming i is the imaginary unit, use i as a variable instead.
Just multiply like you would ordinarily, for example: \[(1-i)(1+2i) = 1*1 + 1*2i - 1*i -i*2i = 1 + 2i - i -2i^2 = 1 +i -2i^2\]Now remember that \(i^2=-1\) and we get:\[1+i-2i^2=1+i-2(-1)=1+i+2=3+i\]
Simplify and show you work \[\sqrt{-24}\]
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