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Mathematics 16 Online
OpenStudy (anonymous):

Find the area of a trapezoid. Leave your answer in simplest radical form.

OpenStudy (anonymous):

OpenStudy (whpalmer4):

what's the formula for the area of a trapezoid?

OpenStudy (anonymous):

A = (b1 + b2/2)*h

OpenStudy (whpalmer4):

Okay, which of those quantities do you know, and which don't you know?

OpenStudy (anonymous):

I know base 1 is 7 and that the height is 5, but I don't know base 2.

OpenStudy (whpalmer4):

Okay. Let's look at the triangles. How about the triangle on the right, can you figure out its dimensions?

OpenStudy (anonymous):

Wait, what do you want to know? ...It's embarrassing how bad I am at math.

OpenStudy (whpalmer4):

Well, can you tell me the base and height and angles of that triangle?

OpenStudy (whpalmer4):

Hint for the height: the thing that makes up the height leg is a square...

OpenStudy (anonymous):

Like I know that it is isosceles based on the angle measures and they are both 5

OpenStudy (whpalmer4):

Okay, that's good, so what are the two angles (besides the 90 degree one)?

OpenStudy (anonymous):

45 and 45

OpenStudy (whpalmer4):

Right. Okay, so we know that it has angles 45, 45, 90, and legs 5, 5, sqrt(50). What about the other triangle?

OpenStudy (anonymous):

It's the same

OpenStudy (whpalmer4):

we know that because...

OpenStudy (anonymous):

they have congruent angle measures and side lengths?

OpenStudy (whpalmer4):

right! so, now do we have enough information to find the longer base?

OpenStudy (anonymous):

Yes

OpenStudy (whpalmer4):

and you say you're bad at math :-)

OpenStudy (anonymous):

Ha I am. So what do I use to find it?

OpenStudy (whpalmer4):

well, isn't it the base of the left triangle + the base of the square + the base of the right triangle?

OpenStudy (anonymous):

Wow, I am such an idiot. That is really obvious. Thank you.

OpenStudy (whpalmer4):

well, not quite so obvious overall — the diagram doesn't make it look like the answer you get, does it?

OpenStudy (whpalmer4):

whenever you see "not to scale", that's often code for "it really looks much different" :-)

OpenStudy (anonymous):

True spit. So is it 85?

OpenStudy (whpalmer4):

oh, wait, I did misspeak, the thing in the middle isn't a square, it's a rectangle, but that didn't matter for finding the sides of the triangles...

OpenStudy (anonymous):

Ok good haha. Thanks again!

OpenStudy (whpalmer4):

so let's see, the top dimension is 7, the bottom dimension is 5+7+5 = 17, the height is 5, so our area should be 1/2(7+17)*5 = ?

OpenStudy (whpalmer4):

we can check a different way, by adding the areas of the rectangle and two triangles. rectangle is 5x7 = 35 triangle is 1/2 b h = 1/2 * 5 * 5 = 25/2, we've got 2 of them, so 2 * 25/2 = 25 rectangle + triangles = 35 + 25 = 60

OpenStudy (anonymous):

Sweet. I got it right!

OpenStudy (whpalmer4):

what was the 85 you mentioned?

OpenStudy (anonymous):

85 cm^2 is the answer

OpenStudy (whpalmer4):

not for the drawing I'm looking at...

OpenStudy (whpalmer4):

The two triangles put together make a 5x5 square, area = 25 cm^2 The rectangle is 5x7 = 35 cm^2 25 + 35 = 60 cm^2 for the whole thing.

OpenStudy (anonymous):

Oh. Okay. Thanks!

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