Mathematics
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OpenStudy (anonymous):
Help pleaseee @jim_thompson5910 @Mertsj
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OpenStudy (anonymous):
OpenStudy (loser66):
you have formula for a circle is x^2 +y^2 = r^2 in which r is radius,
your circle is x^2 +y^2 = 169
see the link?
OpenStudy (anonymous):
no
OpenStudy (mertsj):
The equation of a circle is:
\[(x-h)^2+(y-k)^2=r^2\]
OpenStudy (mertsj):
(h,k) is the center.
What is the center of your circle?
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OpenStudy (anonymous):
0?
OpenStudy (mertsj):
The center has to have an x and a y coordinate.
OpenStudy (anonymous):
how do i find the center
OpenStudy (mertsj):
Look at the picture.
OpenStudy (anonymous):
ok im looking
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OpenStudy (mertsj):
Where do those two lines cross?
OpenStudy (anonymous):
what lines?
OpenStudy (anonymous):
im confused
OpenStudy (mertsj):
The two lines with arrows on the ends
OpenStudy (mertsj):
The only two lines in your picture.
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OpenStudy (anonymous):
0,0?
OpenStudy (mertsj):
I think sometimes they are called coordinate axes.
OpenStudy (mertsj):
Yes. They cross at (0,0) and that is the center. So the equation of your circle now becomes:
OpenStudy (mertsj):
\[(x-0)^2+(y-0)^2+=r^2\]
OpenStudy (mertsj):
Which is the same as:
\[x^2+y^2=r^2\]
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OpenStudy (mertsj):
And, of course, r is the radius so r^2 is the radius squared.
OpenStudy (mertsj):
Are you with me so far?
OpenStudy (anonymous):
yes
OpenStudy (mertsj):
So compare that equation with the equation given in your problem:
OpenStudy (mertsj):
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