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Mathematics 54 Online
OpenStudy (anonymous):

Help pleaseee @jim_thompson5910 @Mertsj

OpenStudy (anonymous):

OpenStudy (loser66):

you have formula for a circle is x^2 +y^2 = r^2 in which r is radius, your circle is x^2 +y^2 = 169 see the link?

OpenStudy (anonymous):

no

OpenStudy (mertsj):

The equation of a circle is: \[(x-h)^2+(y-k)^2=r^2\]

OpenStudy (mertsj):

(h,k) is the center. What is the center of your circle?

OpenStudy (anonymous):

0?

OpenStudy (mertsj):

The center has to have an x and a y coordinate.

OpenStudy (anonymous):

how do i find the center

OpenStudy (mertsj):

Look at the picture.

OpenStudy (anonymous):

ok im looking

OpenStudy (mertsj):

Where do those two lines cross?

OpenStudy (anonymous):

what lines?

OpenStudy (anonymous):

im confused

OpenStudy (mertsj):

The two lines with arrows on the ends

OpenStudy (mertsj):

The only two lines in your picture.

OpenStudy (anonymous):

0,0?

OpenStudy (mertsj):

I think sometimes they are called coordinate axes.

OpenStudy (mertsj):

Yes. They cross at (0,0) and that is the center. So the equation of your circle now becomes:

OpenStudy (mertsj):

\[(x-0)^2+(y-0)^2+=r^2\]

OpenStudy (mertsj):

Which is the same as: \[x^2+y^2=r^2\]

OpenStudy (mertsj):

And, of course, r is the radius so r^2 is the radius squared.

OpenStudy (mertsj):

Are you with me so far?

OpenStudy (anonymous):

yes

OpenStudy (mertsj):

So compare that equation with the equation given in your problem:

OpenStudy (mertsj):

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