Ask your own question, for FREE!
Physics 7 Online
OpenStudy (anonymous):

if v = At^3 - Bt^4 what are the dimensions of A? what are the dimensions of B?

OpenStudy (anonymous):

dimention for v must be length/time if it is velocity or speed so \[v = t ^{3} (A - Bt)\] so dimentions for (A - Bt) must be length/time^3 and thus A has dimentions length/time^3 and B length/time^4

OpenStudy (anonymous):

As there are two unknowns in one equation, A and B have to be expressed with respect to each other. v = d/t Therefore the equation can be written as d/t = t^3(A-Bt) d/t^4 = A-Bt So A = d/t^4 + Bt and B = t^-1(A-dt^-4)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
17 hours ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
20 hours ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Arizona: does anyone know the percentage rate of 30,000 and 40,000
1 week ago 0 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!