Question

how do i find the slope intercept form for the points (-8,6) (1,-9)

Answer 1

first find the slope of the line through the two points


m = (y2-y1)/(x2-x1)



m = (-9-6)/(1-(-8))



m = (-9-6)/(1+8)



m = (-15)/9



m = -5/3

Answer 2

now turn to y = mx+b form, plug in the slope and one given point, then solve for


y = mx+b

y = (-5/3)x + b ... plug in the slope

6 = (-5/3)(-8) + b ... plug in the first point

6 = 40/3 + b

solve for b, I'll let you finish up

Answer 3

so to solve for b i will just bring the 40/3 and end up subtracting 6- 40/3 then i will be done?

Answer 4

yep

Answer 5

6 - 40/3 is what

Answer 6

-22/3

Answer 7

perfect

Answer 8

so

y = mx + b

turns into

\[\large y = -\frac{5}{3} - \frac{22}{3}\]

Answer 9

but you still leave space to plug in x right?

Answer 10

such as y= -5/3 (x) - 22/3

Answer 11

oh sry, meant to say

\[\large y = -\frac{5}{3}x - \frac{22}{3}\]

Answer 12

yeah you got it

Answer 13

perfect thanks so much

Answer 14

you're welcome