Please help! Find the surface area of the pyramid to the nearest whole number.
two parts to this: find the area of one of the triangles making up the top, and find the area of the base. Any idea on how to proceed with either?
Would one of the triangles be 80?
Looks like it...
A couple of approaches for the base. There's certainly a formula involving the apothem, which they give us. Or, you could figure out 1/6 of the base as a pair of right triangles, given that you know the apothem and the length of the sides...
What is the formula?
For a regular \(n\)-sided polygon of side length \(s\) and apothem \(a\), the area is given by \[A = \frac{n s a}{2}\]where \(p\) is the perimeter.
what is the apothem?
If you go the triangle approach, |dw:1369610604331:dw|
The apothem is the line from the center to the center of the side of the polygon
\[a=5\sqrt{3}\] in this problem
Ok, so my equation would be A = 6 * 10 * 5sqrt3 / 2
yes. and if you did the triangles, looking at my diagram, each 1/6th of the base would be \(\frac{1}{2} ( 5) 5\sqrt{3}\) which if multiplied by 6 gives you the same result.
Well, you add the area of the base, + 6 * the area of a side (because there are 6 sides)
i think I got it. It's 740 right?
Yes!
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