x+y=3 and 2x+2y=6
The second equation is just double the first, so the solution of this system is all pairs (x,y) satisfying x+y=3.
These equation do not have a solution because one is twice the other therefore independent. For solution to be obtainable equation must be independent.
Actually it has infinitely many solutions. For example, (0,3) or (1,2) or (100,-97) ... See my previous post for the way to express the complete solution set.
I know there lines coincide or are parallel, but when taking a difference you get zero indicating no single intersection which is required for solution
The lines coincide. Every point on the line, either line, is a solution. This should not be confused with linear independence or "no solution."
Actually the are parallel, its only when you multiply the first equation by 2 do they coincide. y=mx+b (2y)=m(2x)+2b do these to equation coincide if you graph them as is?
KenLJW please excuse me, and with all due respect, I believe you are mistaken.
2(y=mx+b) y=mx+2b y=mx which is the solution of infinite points notice these lines are parallel
To make it more clearly y=mx+b y=mx+2b 2(y=mx+b) -(y=mx+2b)=(y=mx)
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