What is the area of triangle ABC to the nearest tenth of a square meter?
|dw:1369613109191:dw| @whpalmer4
well, what can we conclude about this triangle?
Ohh, I just realized, it's iscoceles (however you spell that)
right.
Oh wait, I think i got it, I find the third side, divide it in half and then I can find the height of the triangle and then the area
well, yes, you can do that. how would you do it?
I use sin(36 degrees)=x/70 and I get 41.145 for the third side, then I divide that by two to get 20.5725 and now I use the pythagorean theorem to find the height
no, it isn't a right triangle, so your trig isn't quite right...
Oh yeah, forgot we can't do trig... what do I do then?
well, we could...you'd bisect that 36 degree angle and make two right triangles. then you could do sin(18 degrees) = (x/2)/70
Another way would be with the law of sines as in the previous problem — because this is an isosceles triangle and we know that the different angle is 36 degrees, we can figure out the two identical angles by subtracting from 180 and dividing by 2 or we could use the side angle side rule for the area of a triangle. that is \(A = s_1 * s_2 * \sin(\theta)\) where \(s1, s2\) are the two sides we know and \(\theta\) is the angle between them.
I use sin(36 degrees)=x/70 and I get 41.145 for the third side, then I divide that by two to get 20.5725 and now I use the pythagorean theorem to find the height almost.... use the Law of Sines to find the 3rd side
@phi but it's an iscoceles triangle, you can't do sin until u bisect?
no, he was quoting what you said...
Ohh, lol my bad xD
it seemed awefully familiar
palmer's idea is the nicest way... but if you are learning how to use the Law of Sines you could do this |dw:1369614158808:dw|
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