Simplify -14x^3/ x^3 - 5x^4
this is the same as the last question you asked. the steps are the same
would x not equai 1/5 and 0 or just 1/5 ?
you're trying to simplify yes? not solve for x
but i also need to find what x doesnt equal
what happens if x = 0?
then theres no solution
why is there no solution?
looks like there is a solution to me
then is it 0?
how does it show that it cant be 1/5?
because if x is 1/5, then the denominator would be 0... and we can't divide be 0
be careful when you simplify though, because when you bring out the x^3.. that actually does still exist. so x cannot be 0 either
oh. ok that makes sense x) i thought there was a special way to figure it out. not just plug it in
when we simplify, we are just reducing terms to make it easier to picture. but in this case we can factor out a x^3 from the top and bottom, which what really means is we multiply \[\frac{ 14 }{ 5x-1 }\] by \[\frac{ x^3 }{ x^3}\] which means x cannot be 0 either, because then 0 would be in the denominator of that fraction too
so if theres an x on the bottom it cant be zero or a number that cancels out the other number for it to be 0
got it :)
well not exactly in every case. in this example we factored out an x on the top and bottom. but lets say if we factored out \[\frac{ x^3+1 }{ x^3+1 }\] then x can still be 0
what i meant if its connected to another number
connect or not connect... coefficients shouldn't matter
ok
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