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OpenStudy (anonymous):
OpenStudy (anonymous):
well for starters, the expression with the = sign is the graph with only 2 points plotted
and the expression with \[\le -1\] has no solution
OpenStudy (anonymous):
what? i dont get it... what expression with \[\|e - 1 \]
OpenStudy (anonymous):
the last expression...
\[|x-2| \le-1\]
OpenStudy (anonymous):
absolute values are always positive
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OpenStudy (anonymous):
ummm the last expression is |x+2| _< - 1
OpenStudy (anonymous):
ohhh right okay
OpenStudy (anonymous):
oh sorry i thought it said -2 not positive 2, but still it cannot be less than -1
OpenStudy (anonymous):
okay so the last one has no solution
OpenStudy (anonymous):
correct
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OpenStudy (anonymous):
the others??
OpenStudy (anonymous):
i'll solve the first one, then just repeat the steps to find the other answers
\[|x+4| \le2\] means that x + 4 needs to be between -2 and 2
so you get x+4 = -2 and x+4 = 2 to find your endpoints of your domain
so the domain of x is -6 to -2, which would be B
OpenStudy (xanthe):
Modulus will always carry a + & - sign
OpenStudy (anonymous):
for
\[|x| < n\]
can be converted to
\[x<n \]
and
\[x> -n\]