Question

A particle moves along a straight line such that its displacement at any time t is given by S= t 3 - 3t 2 + 2 meter. The displacement when the acceleration becomes zero is

Answer 1

acceleration can be taken by differentiating S twice wrt t ie.

$$S=t^3-3t^2+2\implies \frac{dS}{dt}=3t^2-6t\implies \frac{d^2S}{dt^2}=6t-6$$

when acceleration becomes zero,
$$6t-6=0\implies t=1$$

when t=1,
$$S=1-3+2=0$$

Answer 2

Thnx Badhi