Mathematics
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OpenStudy (anonymous):
log questions:
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OpenStudy (anonymous):
\[\log_{2}3.\log_{3}4 \]
OpenStudy (anonymous):
is equal to
(A)1 (B)2 (C)3 (d)4
OpenStudy (anonymous):
pls help
terenzreignz (terenzreignz):
You need two properties... (not the most well-known log properties, too bad)
terenzreignz (terenzreignz):
The first one being
\[\Large \log_ab = \frac{1}{\log_ba}\]
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OpenStudy (unklerhaukus):
\[\large\boxed{\log_b x=\frac{\log_c x}{ \log_c b}}\]
terenzreignz (terenzreignz):
The second one being what Unkle has already posted :D
terenzreignz (terenzreignz):
I want a box...
\[\Large \boxed{ \log_ab = \frac{1}{\log_ba}}\]
terenzreignz (terenzreignz):
Well, it turns out, the so-called property I posted follows directly from what Unkle posted....
meh, go figure :D
OpenStudy (unklerhaukus):
im not sure why you need the one you posted @terenzreignz
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terenzreignz (terenzreignz):
I was thinking
\[\Large \log_23\cdot\log_34 = \frac{\log_34}{\log_32}=\log_24\]
OpenStudy (anonymous):
\[1/\log_{3}2 . \log_{3}4 \]
OpenStudy (unklerhaukus):
ah, i was thinking
\[\log_23\cdot\log_34=\frac{\cancel{\log 3}}{\log2}\cdot\frac{\log 2^2}{\cancel{\log 3}}\]
terenzreignz (terenzreignz):
Many ways to climb the mountain :D
Signing off...
^.^
OpenStudy (anonymous):
@UnkleRhaukus which property is that
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OpenStudy (anonymous):
and what will be the answer from the options
OpenStudy (unklerhaukus):
pardon?
OpenStudy (precal):
I guess McLove is looking for the final solution
OpenStudy (anonymous):
yes its true i am just verifying my answer
OpenStudy (anonymous):
and thanks
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OpenStudy (unklerhaukus):
what did you get @McLove ?
OpenStudy (anonymous):
2
OpenStudy (precal):
|dw:1369667105672:dw|you are correct
OpenStudy (anonymous):
thanks guys
OpenStudy (precal):
anytime :)
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OpenStudy (agent0smith):
@terenzreignz I've never seen the property you posted, but it makes sense \[\Large \log_ab = \frac{ \log_b b }{ \log_b a } = \frac{1}{\log_ba}\]