how do you solve : $$\frac{7}{4}c-\frac{8}{7}=\frac{13}{4}+\frac{2}{7}c$$

Question

aravindg · Answer

bring  2/7 c to left hand  side

aravindg · Answer

8/7 to right hand side

aravindg · Answer

Then you can add like terms

tkhunny · Answer

Various ways to go about it.  If it were me, I'd multiply the world by 28.

ganeshie8 · Answer

multiply the whole equation with 7*4

andriod09 · Answer

Concidering that @AravindG was helping me, i'll go with his help. Thanks to you guys though. :P

aravindg · Answer

@andriod09  multiplying by 7*4 is better a first step

aravindg · Answer

It makes things easier

anonymous · Answer

$$\frac{ 7 }{ 4 }c - \frac{ 2 }{ 7 }c=\frac{ 13 }{ 4 }+\frac{ 8 }{ 7 }$$
$$\frac{ (49-8) }{ 28 }c=\frac{ 91+32 }{ 28 }$$
Multiply by 28 on both sides
$$(49-8)c=91+32$$
$$41c=123$$
$$c=\frac{ 123 }{ 41 }$$
c=3

aravindg · Answer

omg ^ :)

aravindg · Answer

Any doubts?

andriod09 · Answer

Nope. Thanks guys. I hate fractions, i suck at them, and never get them right.

aravindg · Answer

You see when you multiply by 7*4 you get rid of the fraction ..so it becomes simpler

aravindg · Answer

The qn simply reduces to 

49c -32=91+8c

aravindg · Answer

gt it?