Question

What is the area of this parallelogram?
https://media.glynlyon.com/g_geo_2012/12/img_geou12a_45.gif

Answer 1

A = (b)ase x (h)eight

You can use 8 for the (b)ase and what you first have to get is the (h)eight

sin 60 = h/6 -> h = 6 x sin 60

Answer 2

sin 60 = [sqrt(3)]/2

Answer 3

that's not one of my options though... :T

Answer 4

I didn't give an explicit answer to match up to any option. You have some work to do to get the answer.

Answer 5

What you have to do now is put together the pieces I gave you.

Answer 6

Start with height, what is that? Hint: use my first 2 posts.

Answer 7

spilt the parallelogram in two triangles find the area of the first triangle using 1/2bhsin thita
and muiltiply it with 2

Answer 8

What are your options? You may or may not have to simplify the sqrt(3).

Answer 9

is 24 sqrt3 the answer

Answer 10

48 sqrt3 cm^2
48 cm^2
24 sqrt3 cm^2
24 cm^2

Answer 11

yes it is 24 sqrt 3 cm^2

Answer 12

thanks >.< i should've paid more attention in class so that i could actually understand this stuff

Answer 13

You take that "h" and multiply it by "b". "b" is 8 and h is

6 times sqrt(3)/2

So, A = 8 times 6 times sqrt(3) divided by 2

a = 24 times sqrt(3)

Answer 14

Do you understand the methodology now?

Answer 15

Just being given an answer won't help you, you need to be able to do a similar problem on your own. This explanation I gave you on how to do that will enable you to solve similar problems now.

Answer 16

no im still very confused