Question

I need a reminder on how to solve inequalities! x+3/3x > 2

Answer 1

Subtract 2 from both sides.
Write a common denominator.

Answer 2

Determine for what values of x the fraction is positive.

Answer 3

What do you mean?

Answer 4

I mean subtract 2 from both sides. Can you do that?

Answer 5

yes yes I got that

Answer 6

Write a common denominator. Can you do that?

Answer 7

A common denominator of 3x?

Answer 8

\[\frac{x+3-6x}{3x}>0\]

Answer 9

\[\frac{3-5x}{3x}>0\]

Answer 10

Ignore what @genc said. You cannot multiply both sides by 3x because you don't know if 3x is positive or negative.

Answer 11

ok

Answer 12

Now determine where 3-5x is positive and where it is negative.
Do the same for 3x
The fraction is >0 if both are positive or both are negative.

Answer 13

-5x is negative

Answer 14

Not if x is negative, it isn't.

Answer 15

x+3/3x > 2 ...we multiply with *(3x) so we have
3x^2+3>6x
3x^2-6x>-3 /(3)
x^2-2x>-1
x(x-2)>-1
x1>-1 and x-2>-1
x>1 // so we have two solution X1>-1 and X2>1

Answer 16

@Mertsj ...this is correct