Question

The following experiment was carried out to determine the end point of a neutralization reaction by measuring temperature changes. The student was provided with two solutions:
1) X is 2.0 mol dm^3 NaOH solution.
2) Y is a HCl solution of unknown concentration.
25.0 cm^3 of NaOH was put into a plastic cup and the temperature noted. 5cm^3 of HCl was added and the new temperature noted. This was repeated until a total of 40 cm^3 had been added. The results are shown in the table below:

Answer 1

Total vol. of acid added (in cm^3) Temperature of mixture ( in deg C)
0 ------
5 33.5
10 35.0
15 36.5
20 38.0
25 39.0
30 38.0
35 36.5
40 35.0

i) write an equation for the reaction between NaOH and HCl.
ii) Plot a graph of temperature vs. volume of acid added.
iii) Extend your graph so that it crosses the temperature axis. What is the temperature of the NaOH solution at the beginning of the experiment.
iv) Use the graph in ii) above to determine the volume of acid needed to neutralize 25 cm^3 of NaOH used.
v) Calculate the No. of moles of acid in the volume of acid obtained in iv) above.
vi) From your answer in v) above, Calculate the concentration in mol dm^-3 of HCl in solution Y.


I know its long but i really need help! thanks :)

Answer 2

@kausarsalley

Answer 3

@thomaster @ganeshie8 @karatechopper Help?