Question

x 2 8
--- + --- = ------
x+1 x-1 x^2- 1

Thank You So Much if you help

Answer 1

\[\Large \frac{ x }{ x+1}+\frac{ 2 }{ x-1 } = \frac{ 8 }{ x^2-1 }\]
You can get common denominators for the first two fractions, like so:

\[\Large \frac{ x }{ x+1}*\frac{ x-1 }{ x-1 }+\frac{ 2 }{ x-1 } *\frac{ x+1 }{ x+1 }\]