find the vector v that has a magnitude of 4 and is in the same direction of u, where u=<5,-1>
@e.mccormick
Have you done anything with normalizing vercors to get the unit length?
@e.mccormick what do you get? the answer?
take time, friend,
\(4\frac{\vec{u}}{\|\vec{u}\|}\) by finding the normalized version of the vector, you have the same direction and in a unit vector. Then multiply that by 4 units.
yes, I am with you.
100? \[\frac{4}{\sqrt{5^2+(-1)^2}}(5,-1) \implies \left(\frac{20}{\sqrt{26}}, -\frac{4}{\sqrt{26}} \right) \]
And don't forget the - there.
ok, you are right, my bad.
thanks you guys but i got the answer! lololol.
Hehe. We were just discussing it after the fact. =) And as long as you know the process, you should be able to solve any of them.
@BeautyQueen327 glad to hear it, but it doesn't relate to that any more, we discuss to study, too.
ok ok sorry
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