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There are 36 possible outcomes. (2:1, 3:2, 4:3, 5:4, 6:5, 7:6, 8:5, 9:4, 10:3, 11:2, 12:1) So you just find out how many numbers fit into the requirements, add together the number of outcomes each number has, and divide it by 36.
rolling doubles mean (1,1), (2,2) (3,3), (4,4), (5,5), (6,6) A no. that is evenly divisible by 3 is only 6 (1,6) (2,6) (3,6) (4,6) (5,6) ...... (6,6) is already under the first one. ( 6,1) (6,2) 96,3) (6,4 )) (6,5) ---- again (6,6) is already under one
so there are 16 possible outcomes. total possible outcomes are 36 P = 16/36 = 4/9
OH. Okay, do I put P(a) = 4/9 then?
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Okay, thank you! :) I appreciate it!
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