Question

Please help!!!!!! How do you solve this???
limx→4=(√x)-2/x−4

Answer 1

The function\[\sqrt{x}-\frac{2}{x}−4\] is continuous at x=4 so you can just plug in 4 everywhere you see x

Answer 2

Sorry -- the actual equation looks like this\[\lim_{x \rightarrow 4} = \frac{ \sqrt{x}-2 }{ x-4 }\]

Answer 3

The result is 0/0 therefore use L'Hospital Rule
N' = 1/2x
D' = 1
N'/D' = 1/2x as x goes to 4, 1/8

Answer 4

thanks!