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Chemistry 20 Online
OpenStudy (anonymous):

Balance the equation using the half-reaction method: Label each half-cell as being oxidized or reduced. N2(g)+H2(g)→NH3(g)

OpenStudy (anonymous):

Balance the equation using the half-reaction method: Label each half-cell as being oxidized or reduced. \[N _{2}(g)+H _{2}(g)→NH _{3}(g)\]

OpenStudy (anonymous):

this equation involves hydrogen. It is my understanding that there is an exception in oxidation # when is comes to hydrogen.

thomaster (thomaster):

Do you know what the half reactions are?

OpenStudy (anonymous):

Yes! But how do i solve one with a compound at the right end of the arrow?

OpenStudy (anonymous):

sry...my computer froze for a moment

thomaster (thomaster):

hmm why do you need to balance it with halfreaction method? You can easy balance this one by counting elements. on the left is 2xH and 2xN on the right is 3xH and 1xN now you play a little with both sides untill there are equal amounts of elements on both sides. the H is uneven so you put a 2 before NH3. it'll be N2+H2-->2NH3 Now there are 2 N's on both sides but 2H on the left and 6H on the right Just add coefficient 3 before H3 and it's balanced \(N_2+3H_2\to 2NH_3\)

OpenStudy (anonymous):

thank you

thomaster (thomaster):

no problemo \(\Huge \color{red}{\ddot\smile}\)

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