Question

Help? Attached pic.

Answer 1

a vertical asymptote occurs when the denominator = 0....so set x - 5 = 0

what does x = ?

Answer 2

is the limit -5 if the "-" is after the 5?

Answer 3

I'm not sure what you're asking there... if you mean how you have 5^- that means....as x approaches 5 from the left side

Answer 4

oh okay would x be 0 then?

Answer 5

the limit is negative infinity
a limit cant have an asymptote
5 from the left is pretty much saying 4.9999999999999999999999999999
plug that in and see what you get

Answer 6

\[\lim_{x \rightarrow 5^-}\] means as x approaches 5 from the left (negative) side

\[\lim_{x \rightarrow 5^+}\] means as x approaches 5 from the right (positive) side

and no...I meant....how does THIS equation = 0

x - 5 = 0

x = ? *this will be your vertical asymptote

Answer 7

And yes as @zzr0ck3r has said....if you plug in a number VERY close to 5...from the negative (less than 5) side....a.k.a 4.9999999....you will get

1
------
a VERY small negative number


this DOES equate to -infinity as the limit

Answer 8

5.... and so it would be -infinity, x=5!

Answer 9

is that right?

Answer 10

That would be correct yes...vertical asymptote at x = 5....and limit = -infinity

Answer 11

thanks again!