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Find the center + radius of the circle: Equation: (x+2)^2 + (y+10)^2 = 4
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(-2;-10) i think
I'm sure agent0smith will explain why
\[\Large (x+2)^2 + (y+10)^2 = 4\] This is the standard form of a circle, with center (h, k) and radius r. \[\Large (x-h)^2 + (y-k)^2 = r^2\] Now compare that to yours: \[\Large \left( x-(-2) \right)^2 + \left( y- (-10)\right) ^2 = 2^2 \]
basically you have an equation: (x-h)^2+(y-k)^2=r^2 and (h;k) is the center and r is the radius
thank you guys im really not that good in math
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so it's -2 and - 10 and radius is 4?
Center is correct. Pay more attention to the r^2 in the equation above.
Center (-2, -10)
2?
Correct.
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thank you!!!!!
:)
Welcome :)
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