Question

a third degree polynomial with 1 and -1 as its only zeroes

Answer 1

since we know that 1 and -1 are zeros, we can conclude

(x-1)(x+1) is part of the solution

however that will only give us a 2nd degree polynomial

since it states that only 1 and -1 are zeroes, that means there are 2 solution

it could either be

(x-1)(x+1)^2 or (x-1)^2(x+1)

Answer 2

Thank you