Question

Number 4: http://imageshack.us/photo/my-images/7/scannu.png/

Answer 1

@Jhannybean

Answer 2

Write them here

Answer 3

Well...here's a little hint,... use common denominators!

Answer 4

I'm not sure how...

Answer 5

whaat i told u this already didnt i

Answer 6

nooo... lol

Answer 7

...

Answer 8

oh hey dan.

Answer 9

hey! teach him common denominator T_T

Answer 10

Dan Jhanny was helping me on a different question I reposted this.

Answer 11

i will, just give me a little time.

Answer 12

dan, http://openstudy.com/study#/updates/51a3cb2ae4b0aa1ad8879cea

Answer 13

2/(x-3) -4/(x+3)
[2(x+3)-4(x-3)]/(x-3)(x+3)
(-2x+18)/(x-3)(x+3)
-2(x-9)/(x-3)(x+3)=-2(x-9)/(x^2-9) |x| not equal to 3

Answer 14

Thanks! I got the first part just needed some guidance

Answer 15

Wait isn't the restriction x does not equal 9

Answer 16

@KenLJW

Answer 17

So for this one you will be solving for x.
\[\frac{ 2 }{ (x-3) }-\frac{ 4 }{ (x+3) }=\frac{ 8 }{ (x^2-9) }\]\[\frac{ 2\color{red}{(x+3)} }{ \color{red}{(x-3)(x+3)}}-\frac{ 4\color{red}{(x-3)} }{ \color{red}{(x-3)(x+3)} }=\frac{ 8 }{ \color{red}{(x^2-9)} }\]\[\large \frac{ 2x+6 }{ \color{red}{(x^2-9)} }-\frac{ 4x-12 }{ \color{red}{(x^2-9)} }= \frac{ 8 }{ \color{red}{(x^2-9)} }\] combine the two fractions on the left hand side. \[\large \frac{ (2x+6)-(4x-12) }{ \color{red}{(x^2-9)} }= \frac{ 8 }{ \color{red}{(x^2-9)} }\] Simplify \[\large \frac{ 2x-4x-6 }{ \color{red}{(x^2-9)} }=\frac{ 8 }{ \color{red}{(x^2-9)} }\]\[\large \frac{ -2x-6 }{ \color{red}{(x^2-9)} }= \frac{ 8 }{ \color{red}{(x^2-9)} }\] Now you'll be solving for x,so you'll move the fraction on the right over to the left \[\large \frac{ -2x-6 }{ \color{red}{(x^2-9)} }-\frac{ 8 }{ \color{red}{(x^2-9)} }=0\]

Answer 18

OHHH

Answer 19

See above x^2-9 can't be 0 |x| not equal 3

Answer 20

\[\large \frac{ -2x-14 }{ \color{red}{(x^2-9)} }\]\[\large \color{green}{-2}(x+7) = 0\] and \[\large \color{red}{(x^2-9)}=0\]

Answer 21

practice ur algebra get fast!

Answer 22

yes, remember, \[\large \sqrt{x^2} = |x|\]

Answer 23

Jhan are you indian?

Answer 24

@Jhannybean

Answer 25

she is angelian

Answer 26

from the land of angels xD

Answer 27

I'm an alien.

Answer 28

Ken got the right format, that |x| = 3

Answer 29

lol