Question

How to integrate to int ( 1/(e ^(3y) -1 ) dy

Answer 1

that would be e^(3y)
what is the anti derivative of e^(3y)?

Answer 2

does that say 1/((e^(3y)) - 1)?

Answer 3

\[ 1 + \frac{1}{e^{3y} - 1} = \frac{e^{3y}}{e^{3y} - 1}\]

Answer 4

\[\int\limits ( 1 / (e^(3y) -1 ) dy \]

Answer 5

basically int ( e^ (3y) - 1) -1 dy

Answer 6

any solution , I really have forgotten calculus .

Answer 7

can you integrate the right hand side of the above expression?

Answer 8

yes

Answer 9

The full equation is (dy/dx) = x^2(e^3y - 1)

Answer 10

huh?? that's a Differential equation

Answer 11

these are not the same questions:)

Answer 12

So you started with this,
\[\large \frac{dy}{dx}=x^2(e^{3y}-1)\]
You separated variables and got stuck here on this left side?\[\large \int\limits \frac{dy}{e^{3y}-1}=\int\limits x^2 dx\]

Oh.. you're offline -_-