Question

1. Divide.
(18x^3+12x^2-3x)/6x^2

2. Divide.
(2x^3-x^2-24x+12)/(2x-1)

3. Simplify
2a+2/a^2-1

4. What is the undefined value of 3b^2+13b+4/b+4

5. Multiply.
(x^2-x-42/x-8)(x^2-64/9x+54)

6.Divide
(x^2+9+20/x^2-25) / (x+4/x-4)

7.Add.
8+ (x-1/x+4)

8. Subtract (x^2-1/x^2-x-2) - (x-1/x-2)

9. Solve
(10/3x)+(4/3)=(7+x/2x)

10. Solve (x+12/x+4)=(x/x+8)

11. A group of college students is volunteering for Homes for the Community during their spring break. They are putting the finishing touches on a house they built. Working alone, Wade can paint a certain room in 7 hour

Answer 1

5 dollars each

Answer 2

I have you give you $5 per answer

Answer 3

??

Answer 4

yes

Answer 5

11 seems incomplete?

Answer 6

forget it man..

Answer 7

okay 90 percent discount for u

Answer 8

um no.

Answer 9

100 percent discount?

Answer 10

yeah you're not getting any of my money, you don't have to answer the questions if you dont want to

Answer 11

i am just joking

Answer 12

oh, sorry, talking to stragers online kinda freaks me out in the first place

Answer 13

i got problem 11 dont worry about that one

Answer 14

@passive13

Answer 15

(4/b)) NUMBER 4

Answer 16

2/a-1 NUMBER 3

Answer 17

number 7... you know how to add fractions...?
eg
3/5 + 7/9 = ?
so you find a common denominator (the bottom number), usually by multiplying the denominator of one by top and bottom of the other

so:
\[\frac{ 3}{ 5 } + \frac{ 7 }{ 9 } \rightarrow \frac{ 3\times 9 }{ 5\times9 } +\frac{ 7\times 5 }{ 9\times 5 } \]

then you can add the top line if the denominators match

\[\frac{ 27 }{ 45 } + \frac{ 35 }{ 45 } = \frac{ 27+35 }{ 45 } = \frac{ 62 }{ 45 }\]

so use the same principal for Q7

Answer 18

so 8+ (x-1/x+4)

is the same as:

\[\frac{ 8 }{ 1 } + \frac{ (x-1) }{ (x+4) } = \frac{ 8\times(x+4) }{ 1\times(x+4) } + \frac{ 1\times(x-1) }{ 1(x+4) }\]