Ask your own question, for FREE!
Chemistry 19 Online
OpenStudy (anonymous):

Please help chem final tomorow! A sample of 0.78 moles of a metal M reacts completely with excess chlorine to form 45.58 grams of MCl. How many moles of Cl are in the sample of MCl that forms?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (chmvijay):

can you write the balanced reaction for this

OpenStudy (anonymous):

I'm not sure how exactly since M isn't a real element, but I assume it's M+Cl->MCl

OpenStudy (chmvijay):

ok let me check it right now i am busy i will let u know after some time:)

OpenStudy (anonymous):

ok:)

OpenStudy (anonymous):

@Nurali @whpalmer4

OpenStudy (anonymous):

@AwkwardAvoidnceViking

OpenStudy (anonymous):

the compound you form is MCl, meaning that for every atom of M it uses 1 atom of Cl

OpenStudy (anonymous):

from this and the number of moles of M are used you should be able to tell how many moles of Cl are used

OpenStudy (anonymous):

So it would be the same number, 0.78. You don't have to do anything with the grams?

OpenStudy (anonymous):

oh the second part of the question asks how many grams of M there are

OpenStudy (anonymous):

so the weight of the complete compound is 45.58 grams? mass is not created or destroyed you have .78 moles of Cl, how much mass is that?

OpenStudy (anonymous):

27.651g so the mass of M would be 17.929?

OpenStudy (anonymous):

looks like it

OpenStudy (chmvijay):

hey its 0.78 moles of Cl :)

OpenStudy (anonymous):

yeah thank you:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!