Please help chem final tomorow! A sample of 0.78 moles of a metal M reacts completely with excess chlorine to form 45.58 grams of MCl.
How many moles of Cl are in the sample of MCl that forms?
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OpenStudy (anonymous):
@ganeshie8
OpenStudy (chmvijay):
can you write the balanced reaction for this
OpenStudy (anonymous):
I'm not sure how exactly since M isn't a real element, but I assume it's M+Cl->MCl
OpenStudy (chmvijay):
ok let me check it right now i am busy i will let u know after some time:)
OpenStudy (anonymous):
ok:)
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OpenStudy (anonymous):
@Nurali @whpalmer4
OpenStudy (anonymous):
@AwkwardAvoidnceViking
OpenStudy (anonymous):
the compound you form is MCl, meaning that for every atom of M it uses 1 atom of Cl
OpenStudy (anonymous):
from this and the number of moles of M are used you should be able to tell how many moles of Cl are used
OpenStudy (anonymous):
So it would be the same number, 0.78. You don't have to do anything with the grams?
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OpenStudy (anonymous):
oh the second part of the question asks how many grams of M there are
OpenStudy (anonymous):
so the weight of the complete compound is 45.58 grams?
mass is not created or destroyed
you have .78 moles of Cl, how much mass is that?
OpenStudy (anonymous):
27.651g so the mass of M would be 17.929?
OpenStudy (anonymous):
looks like it
OpenStudy (chmvijay):
hey its 0.78 moles of Cl :)
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