|x/3+1|=6 A. {-7, 15} B. {-21, 15} C. {7, 15} D. {-15, 21}
\[\large \left|\frac{x}3+1\right|=6\]
All this really means is that you have two equations to solve. \[\Large \frac{x}3+1 = 6\] and \[\Large \frac{x}3+1 = -6\]
I just don't know how to do it with fractions exactly... @terenzreignz
Well then, you can always multiply everything by 3, thereby cancelling out the denominator. \[\Large x + 3 = 18\] and \[\Large x+3 = -18\]
oh, right right. After that would I divide?
@terenzreignz
Not yet, you solve for x, on both equations.
would it be {15, -21}
Yes, indeed :)
YES! Thank you so much! :)
\[\left| \frac{ x }{3 }+1 \right|=6\] \[\left| \frac{ x+3 }{3 } \right|=6,\left| x+3 \right|=18,x+3=\pm18\] now you can solve the two equations.
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