H2PO4- ⇄ OH- + HPO4- OH- ions are added to this system. What happens? I know that the OH- will join with the H+ to form water and that the equilibrium will shift right. BUT why will it shift right?
a system at equilibrium is like a delicately balanced see-saw. a stress to one side will make the system shift to re-establish a balance and restore equilibrium. by addin OH- ions to the product side, you've made the products "too heavy" so the system has to shift away from that stress
so then shouldn't the backward reaction be favoured?
sorry, i wrote the question wrong
it will. we will get a decrease in the HPO4- concentration, and an increase in the H3PO4 concentration
the products are H+ and HPO4-
ok, then the situatino changes silghtly, but not much. You've got H+ and HPO4- ions as products. When you add OH- ions, which product are they likely to react with?
with H+ to produce water
so what does that do to the H+ concentration?
it increases the H+ conc
it's goign to DECREASE the H+ concentration, because the H+ ions will be used up by the addition of OH- ions
ohhhhh
so that means the stress isn't an addition on one side, it's a REMOVAL of product. so that stresses the system to move towards what side?
the equilibrium will shift right as there will be a greater conc of the product. by shifting right, a greater amount of products will be formed, restoring equilibrium
am i correct?
you're mostly right
reactants**
that's better
reactant***
haha, thanks
yw
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