How many molecules are present in 936 g of glucose (C6H12O6)?
(The molar mass of glucose = 180.16 g/mol.)

Question

How many molecules are present in 936 g of glucose (C6H12O6)?
(The molar mass of glucose = 180.16 g/mol.)

chmvijay · Answer

180.16 g of glucose contains 6.023*10^23 molecules of glucose
936 gram of glucose contains = 6.023*10^23 *936    /180.16 =  find it

anonymous · Answer

$$n=\frac{ N }{ L }$$
since
$$n=\frac{ m }{ M }$$
what you now get is,
$$\frac{ m }{ M }=\frac{ N }{ L }$$

anonymous · Answer

n=no. of moles
N=Number of particles (atoms, molecules, ions....)
L=Avogadro's constant (6.02*10^23)
m=mass
M=Molar mass

anonymous · Answer

plug in the values you have and find N (number of molecules).