Ask your own question, for FREE!
Chemistry 15 Online
OpenStudy (anonymous):

Hi, can some one please help me :) Iodine-131 has a half-life of 8 days. In how many days will a 1 kg sample of iodine-131 decay and reduce to 0.0625 kg of iodine-131? 8 days 16 days 24 days 32 days

OpenStudy (anonymous):

do u think u know this @JFraser

OpenStudy (jfraser):

half-life always means the same percentage of a radioactive substance will decay over that given period of time. In order for 1000g of I-131 to decay to 62.5g of I-131, you have to find out what percentage remains, and what percentage has decayed. What percentage of 1000g is 62.5g?

OpenStudy (jfraser):

Or, you can think of it this way: How many times can you cut 1000g in half before you get to 62.5g?

OpenStudy (anonymous):

okay , let me try to figure this out

OpenStudy (anonymous):

oh, the answer is 16 thanks so much for the help!, i am giving u a medal. If you dont mind can u help me with another one?

OpenStudy (jfraser):

the answer is not 16 days

OpenStudy (anonymous):

its not?

OpenStudy (jfraser):

each half life is 8 days. after each half life, the amount of I131 remaining will be cut in half. So...

OpenStudy (anonymous):

oh 4

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

WAIT!

OpenStudy (anonymous):

THERE IS NO 4 I AM CONFUSED!

OpenStudy (jfraser):

0 days: 0 half-lives: 1000g left 8 days: 1 half-life: 500g left (500g decayed) 16 days: 2 half-lives: 250g left (750g decayed) ... keep going dividing the mass

OpenStudy (jfraser):

it's 4 HALF-LIFES, but each half-life takes 8 days

OpenStudy (anonymous):

oh, so 32 correct?

OpenStudy (anonymous):

lol i suck at science..good at everything else just not science :(

OpenStudy (anonymous):

but if you feel like it, can u help me with anther one, it is sort of like this

OpenStudy (anonymous):

One scientist kept 20 grams of a radioactive material in a container. What will be the mass of the radioactive material left in the container after 2 half lives? 4 grams 5 grams <<<<-------- 10 grams 40 grams that is what i think

OpenStudy (anonymous):

@JFraser

OpenStudy (jfraser):

looks right to me

OpenStudy (anonymous):

thanks man, is there anyway i can give u 2 medals lol?

OpenStudy (jfraser):

instead of asking several questions in the same post, close the one and open a new one

OpenStudy (anonymous):

okay i will thanks :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!