Question

(sec^2x-1)/(sin^2x)

Answer 1

sec^2 x - 1
What is this equal to?
^_^

Answer 2

\[\tan^2x + 1 = \sec^2x\]

Answer 3

so it would be (tan^2x+1)/(sin^2x)

Answer 4

But remember, there's a -1 in the numerator :)

Answer 5

the one would cancel out?

Answer 6

Yup.

Answer 7

so (tan^2)/(Sin^2)

Answer 8

Yes, and simplify that as you will :D

Answer 9

would it be sec^2x

Answer 10

Great work :D

Answer 11

okay i have one more: sec^4-tan^4x

Answer 12

Difference of two squares, facturrrrr....

Answer 13

huh? I'm lost

Answer 14

x^2 - y^2 = (x+y)(x-y)

Answer 15

This is all foreign to me :(

Answer 16

But this should have been second nature by now... anyway
sec^4 x - tan^4 x = (sec^2 x - tan^2 x)(sec^2 x + tan^2 x)

Answer 17

is tan^2 = 1 ?

Answer 18

nope.

Answer 19

dang.

Answer 20

the answer is sec^2+ tan^2x

Answer 21

That is correct :)

Answer 22

(sinx*secx)/cscx