Question

Take the reaction: NH3 + O2 NO + H2O. In an experiment, 3.25 g of NH3 are allowed to react with 3.50 g of O2.

a. Which reactant is the limiting reagent?

b. How many grams of NO are formed?

Answer 1

can someone pls help. i have an exam tomorrow

Answer 2

@.Sam. @AravindG @ganeshie8

Answer 3

Convert grams of NH3 and grams of O2 into moles, then see which is larger

Answer 4

i have found my limited reagent bt just confused abt 2nd part where i have to find mass

Answer 5

Well since the mole ratio of O2 and NO is 1, so
n(O2)=n(NO)=0.1094mol

Answer 6

Then just multiply 0.1094mol by its molar mass and you'll get the mass

Answer 7

its molar mass=NO's molar mass

Answer 8

so.. is the and 6.0928

Answer 9

ans*

Answer 10

Molar mass of NO=14+16=30g/mol
Using 0.1094mol,
\[0.1094mol \times 30g/mol=3.282g~of~NO\]

Answer 11

sory is it 5.7

Answer 12

but i get 5.7 if i do this

Answer 13

Did you use a calculator, lol

Answer 14

um..yess lol

Answer 15

Yeah just multiply
0.1094 by 30

Answer 16

i did

Answer 17

anyway thank u for showing me how to do it

Answer 18

yw :)