Ask your own question, for FREE!
Chemistry 6 Online
OpenStudy (anonymous):

Ammonium nitrate can decompose explosively when heated. NH4NO3 -> N2O + 2H2O what are changes in the oxidation numbers of two nitrogen atoms in ammonium nitrate when this reaction proceeds?

OpenStudy (chmvijay):

find the oxidation state of N in NH4NO3 and N2O

OpenStudy (anonymous):

Didn't work 😣

OpenStudy (chmvijay):

what didnt work

OpenStudy (anonymous):

I did try to find the ox states of 2 nitrogen atoms that way.. but the answer I get is not right 😒

OpenStudy (chmvijay):

without doing that how can you get the oxidation state

OpenStudy (chmvijay):

and that too wrong :)

OpenStudy (chmvijay):

what is oxidation no of O can you tell

OpenStudy (anonymous):

Well, I didn't get the question just read the mark scheme. In it the ox states of 2 nitrogen atoms are +4, -4

OpenStudy (chmvijay):

O will have always -2 oxidation state since N2O is neutral mean charge on N2O is zero then what will be the charge on N2 and N

OpenStudy (anonymous):

I know that the ox state of O is -2 I

OpenStudy (chmvijay):

then on N2 of N2O what u expect the charge will be

OpenStudy (anonymous):

+1 I guess.

OpenStudy (chmvijay):

On N2 its +2 and on N its is +1 ur right

OpenStudy (chmvijay):

now you consider NH4Cl the charge on NH4 is

OpenStudy (anonymous):

Exactly!

OpenStudy (anonymous):

-4?

OpenStudy (anonymous):

Ohhh, ammonium ion is +1

OpenStudy (chmvijay):

ok then what is charge on each protons of NH4 ion

OpenStudy (chmvijay):

proton will always have +1 charge

OpenStudy (chmvijay):

4 protons will have --- charge

OpenStudy (anonymous):

As there are 4 protons so +1 for each and total are +4 so in finding out the ox state of nitrogen atom it's -4

OpenStudy (chmvijay):

ur right

OpenStudy (chmvijay):

but the total charge on NH4 is +1 u have to deduce one and put the other charge on N

OpenStudy (anonymous):

Charge on nitrogen is -3

OpenStudy (chmvijay):

|dw:1369761962017:dw| you are right

OpenStudy (anonymous):

I knew that already before I did the whole working but I just didn't get this question! :/

OpenStudy (chmvijay):

ok now you got it

OpenStudy (anonymous):

But the answer is not this

OpenStudy (chmvijay):

ok you also find ou the oxidation no of N in NO3 - what will be that

OpenStudy (anonymous):

Charge on nitrate is -1 so ox state of nitrogen is nitrate is +5

OpenStudy (chmvijay):

yaaa ur right

OpenStudy (chmvijay):

so one is +5 and other is -3 in reactant side both get converted to +1 in product side

OpenStudy (chmvijay):

so u have too tell which is oxidized and which nitrogen is reduced can you now do that

OpenStudy (anonymous):

I got the answer right. Thanks for guiding :)

OpenStudy (chmvijay):

ur welcome :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!