Ammonium nitrate can decompose explosively when heated. NH4NO3 -> N2O + 2H2O what are changes in the oxidation numbers of two nitrogen atoms in ammonium nitrate when this reaction proceeds?
find the oxidation state of N in NH4NO3 and N2O
Didn't work 😣
what didnt work
I did try to find the ox states of 2 nitrogen atoms that way.. but the answer I get is not right 😒
without doing that how can you get the oxidation state
and that too wrong :)
what is oxidation no of O can you tell
Well, I didn't get the question just read the mark scheme. In it the ox states of 2 nitrogen atoms are +4, -4
O will have always -2 oxidation state since N2O is neutral mean charge on N2O is zero then what will be the charge on N2 and N
I know that the ox state of O is -2 I
then on N2 of N2O what u expect the charge will be
+1 I guess.
On N2 its +2 and on N its is +1 ur right
now you consider NH4Cl the charge on NH4 is
Exactly!
-4?
Ohhh, ammonium ion is +1
ok then what is charge on each protons of NH4 ion
proton will always have +1 charge
4 protons will have --- charge
As there are 4 protons so +1 for each and total are +4 so in finding out the ox state of nitrogen atom it's -4
ur right
but the total charge on NH4 is +1 u have to deduce one and put the other charge on N
Charge on nitrogen is -3
|dw:1369761962017:dw| you are right
I knew that already before I did the whole working but I just didn't get this question! :/
ok now you got it
But the answer is not this
ok you also find ou the oxidation no of N in NO3 - what will be that
Charge on nitrate is -1 so ox state of nitrogen is nitrate is +5
yaaa ur right
so one is +5 and other is -3 in reactant side both get converted to +1 in product side
so u have too tell which is oxidized and which nitrogen is reduced can you now do that
I got the answer right. Thanks for guiding :)
ur welcome :)
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