Sketch and find the area of the region bounded by the given curves. y = x^2 + 1, y = 3x - 1

Question

Sketch and find the area of the region bounded by the given curves.	y = x^2 + 1, y = 3x - 1

luigi0210 · Answer

Graph the equations

anonymous · Answer

how?

luigi0210 · Answer

|dw:1369758293244:dw|

anonymous · Answer

ok

anonymous · Answer

so the area between those two lines is the bounded region right?

anonymous · Answer

by the way is the graph in the first quadrant?

luigi0210 · Answer

Yes, and yes it is in quad one

anonymous · Answer

okay so what do i do next? after I graph it? do I integrate?

amistre64 · Answer

yes; integrate the difference of the functions along the interval in which they are bounded

anonymous · Answer

sooo i'll be integrating x^2 + 1 and 3x - 1?

amistre64 · Answer

determine when:  f(x) = g(x) to get the interval of [a,b]

then integrate f-g, from a to b

amistre64 · Answer

if you come up with a negative, drop the sign :)

luigi0210 · Answer

Yup, and make sure you are subtracting the top from bottom

amistre64 · Answer

top from bottom is superfluous

amistre64 · Answer

5 - 3 = 2
3 - 5 = -2

your result should be positive, so the only difference is the sign

anonymous · Answer

ok

anonymous · Answer

so i'm integrating x^2 + 1 and 3x - 1? then subtracting top with the bottom?

anonymous · Answer

@dumbcow

anonymous · Answer

@RadEn

dumbcow · Answer

you are integrating the difference of 2 functions

anonymous · Answer

ohh so i'll subtract then integrate the difference of them?