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Mathematics 19 Online
OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

the previous question, we interpreted wrongly

ganeshie8 (ganeshie8):

OpenStudy (anonymous):

we did?

ganeshie8 (ganeshie8):

the horizontal line is not a division line there. it is just a separator ! so the answer wont be 1

ganeshie8 (ganeshie8):

after looking at ur present question, i sensed that. ur quesiton itself is repeating the quesiton two times.

ganeshie8 (ganeshie8):

first time, while asking the q, and second time, while entering the answer. see that ?

OpenStudy (anonymous):

no its supposed to be like this i just did that so you would see where is said to write a fraction

ganeshie8 (ganeshie8):

not this one, im talking about the previous question.

ganeshie8 (ganeshie8):

the answer is not 1 for that. if u want we can rework it :)

OpenStudy (anonymous):

ooo its suppose to be like that

ganeshie8 (ganeshie8):

if you're confident, then fine :) lets work the present problem..

ganeshie8 (ganeshie8):

we need to make the denominators equal, since we are adding a fraction to a normal term.

OpenStudy (anonymous):

ok:)

ganeshie8 (ganeshie8):

look at the given expression, and tell me whats the denominator u see

OpenStudy (anonymous):

wait your right about the last question

ganeshie8 (ganeshie8):

oh how do u knw that

OpenStudy (anonymous):

i just checked with my instructor

ganeshie8 (ganeshie8):

ohk... good you're pretty fast :) lets finish this problem, and we will go back to the previous problem ok

OpenStudy (anonymous):

ok :)

ganeshie8 (ganeshie8):

look at the given expression, and tell me whats the denominator of fraction

OpenStudy (anonymous):

7

ganeshie8 (ganeshie8):

yes, so we need to get the left term 5x also to have that as denominator

ganeshie8 (ganeshie8):

how to do that ?

ganeshie8 (ganeshie8):

\(\large 5x + \frac{3}{7}x\)

ganeshie8 (ganeshie8):

\(\large \frac{7}{7}*5x + \frac{3}{7}x\)

OpenStudy (anonymous):

idk:(

ganeshie8 (ganeshie8):

ive just multiplied the first term with 1.

ganeshie8 (ganeshie8):

7/7 = 1. so thats the trick u need to see :)

ganeshie8 (ganeshie8):

\(\large \frac{35}{7}x + \frac{3}{7}x\)

ganeshie8 (ganeshie8):

now both have the same denominators !

ganeshie8 (ganeshie8):

so you can add the numerators directly now

ganeshie8 (ganeshie8):

\(\large \frac{35x+3x}{7}\)

ganeshie8 (ganeshie8):

\(\large \frac{38}{7}x\)

OpenStudy (anonymous):

38/7?

ganeshie8 (ganeshie8):

yes dont forget the x

OpenStudy (anonymous):

can you help with more?

ganeshie8 (ganeshie8):

now try the previous problem. you should find it easy...

ganeshie8 (ganeshie8):

yea sure

OpenStudy (anonymous):

the question before i think i have to subtract the numerator

ganeshie8 (ganeshie8):

good :) lets workk it

OpenStudy (anonymous):

so it would be 3/b?

ganeshie8 (ganeshie8):

\(\large -\frac{3}{b} + (-\frac{1}{b})\)

ganeshie8 (ganeshie8):

since denominators are same, we can add/subtract the numerators

ganeshie8 (ganeshie8):

\(\large \frac{-3 -1}{b} \)

ganeshie8 (ganeshie8):

\(\large \frac{-4}{b} \)

OpenStudy (anonymous):

thats the correct answer?

OpenStudy (anonymous):

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