Mathematics
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OpenStudy (anonymous):
@ganeshie8
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OpenStudy (anonymous):
ganeshie8 (ganeshie8):
the previous question, we interpreted wrongly
ganeshie8 (ganeshie8):
OpenStudy (anonymous):
we did?
ganeshie8 (ganeshie8):
the horizontal line is not a division line there. it is just a separator ! so the answer wont be 1
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ganeshie8 (ganeshie8):
after looking at ur present question, i sensed that. ur quesiton itself is repeating the quesiton two times.
ganeshie8 (ganeshie8):
first time, while asking the q, and second time, while entering the answer. see that ?
OpenStudy (anonymous):
no its supposed to be like this i just did that so you would see where is said to write a fraction
ganeshie8 (ganeshie8):
not this one, im talking about the previous question.
ganeshie8 (ganeshie8):
the answer is not 1 for that. if u want we can rework it :)
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OpenStudy (anonymous):
ooo its suppose to be like that
ganeshie8 (ganeshie8):
if you're confident, then fine :) lets work the present problem..
ganeshie8 (ganeshie8):
we need to make the denominators equal, since we are adding a fraction to a normal term.
OpenStudy (anonymous):
ok:)
ganeshie8 (ganeshie8):
look at the given expression, and tell me whats the denominator u see
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OpenStudy (anonymous):
wait your right about the last question
ganeshie8 (ganeshie8):
oh how do u knw that
OpenStudy (anonymous):
i just checked with my instructor
ganeshie8 (ganeshie8):
ohk... good you're pretty fast :) lets finish this problem, and we will go back to the previous problem ok
OpenStudy (anonymous):
ok :)
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ganeshie8 (ganeshie8):
look at the given expression, and tell me whats the denominator of fraction
OpenStudy (anonymous):
7
ganeshie8 (ganeshie8):
yes, so we need to get the left term 5x also to have that as denominator
ganeshie8 (ganeshie8):
how to do that ?
ganeshie8 (ganeshie8):
\(\large 5x + \frac{3}{7}x\)
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ganeshie8 (ganeshie8):
\(\large \frac{7}{7}*5x + \frac{3}{7}x\)
OpenStudy (anonymous):
idk:(
ganeshie8 (ganeshie8):
ive just multiplied the first term with 1.
ganeshie8 (ganeshie8):
7/7 = 1. so thats the trick u need to see :)
ganeshie8 (ganeshie8):
\(\large \frac{35}{7}x + \frac{3}{7}x\)
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ganeshie8 (ganeshie8):
now both have the same denominators !
ganeshie8 (ganeshie8):
so you can add the numerators directly now
ganeshie8 (ganeshie8):
\(\large \frac{35x+3x}{7}\)
ganeshie8 (ganeshie8):
\(\large \frac{38}{7}x\)
OpenStudy (anonymous):
38/7?
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ganeshie8 (ganeshie8):
yes dont forget the x
OpenStudy (anonymous):
can you help with more?
ganeshie8 (ganeshie8):
now try the previous problem. you should find it easy...
ganeshie8 (ganeshie8):
yea sure
OpenStudy (anonymous):
the question before i think i have to subtract the numerator
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ganeshie8 (ganeshie8):
good :) lets workk it
OpenStudy (anonymous):
so it would be 3/b?
ganeshie8 (ganeshie8):
\(\large -\frac{3}{b} + (-\frac{1}{b})\)
ganeshie8 (ganeshie8):
since denominators are same, we can add/subtract the numerators
ganeshie8 (ganeshie8):
\(\large \frac{-3 -1}{b} \)
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ganeshie8 (ganeshie8):
\(\large \frac{-4}{b} \)
OpenStudy (anonymous):
thats the correct answer?
OpenStudy (anonymous):