Question

What values for θ(0≤θ≤2π) satisfy the equation 3sinθ = sinθ-1?

Answer 1

Do some algebra on the equation first (simplify)....
subtract sin(theta) from both sides, then divide by sin(theta) on both sides...
what you got left as a result?

Answer 2

I'm so confused.

Answer 3

start with the original equation then subtract sin(theta) from both sides first...

3sinθ = sinθ-1
3sinθ - sinθ = sinθ-1- sinθ
2sinθ = -1

this is the first part. now divide both sides by sin(theta)...

Answer 4

sorry... divide both sides by "2"....

Answer 5

So sinθ = -1/2

Answer 6

ok... do you know what angle(or angles) gives a -1/2 when you take the sine of that angle?

Answer 7

No

Answer 8

have you used the unit circle?

Answer 9

I have not.