Question

Divide...

Answer 1

You may recall that when you divide fractions that you can rewrite the expression as the multiplication of the reciprocal. So your \[\frac{\frac{x^{2}+8x+15}{x^{2}-9}}{\frac{x+5}{x-5}}\] becomes \[\frac{x^{2}+8x+15}{x^{2}-9}*\frac{x-5}{x+5}\]

Answer 2

Do you know where to go from here?

Answer 3

@eSpeX : That's the part I'm having trouble on.

Answer 4

@eSpeX : The step after that, I mean.

Answer 5

I would start by factoring the left hand fraction. I bet there is some simplification that can be done before multiplying.

Answer 6

@eSpeX : Alright. What do I do after I factor it?

Answer 7

What did you get?

Answer 8

What did you get when you factored \[x^{2}+8x+15\]

Answer 9

@eSpeX : (x+5)(x+3)

Answer 10

Exactly, good work.
Now the first part of your equation looks like \[\frac{(x+5)(x+3)}{x^{2}-9}\]So what do you get if you factor the denominator?