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Mathematics 7 Online
OpenStudy (nerdy_3000):

A need someone to check this and if it is wrong can you help me!! And on 45 as well.http://oi42.tinypic.com/fmuh60.jpg

OpenStudy (rajee_sam):

you got no. 44 right. So no. 45 just similar to that

OpenStudy (nerdy_3000):

Thanks!

jimthompson5910 (jim_thompson5910):

see attached for what you got right/wrong

OpenStudy (rajee_sam):

why is 44 wrong?

jimthompson5910 (jim_thompson5910):

for #45, you need to solve the following for x \[\large 12^2 + x^2 = (12+8)^2\]

OpenStudy (rajee_sam):

@jim_thompson5910 , Why is her 44 wrong?

jimthompson5910 (jim_thompson5910):

because \[\large \sqrt{200} \approx 14.142135623731 \approx 14.1\] and NOT 14.2

OpenStudy (rajee_sam):

oh come on!!

OpenStudy (rajee_sam):

her method is absolutely right

jimthompson5910 (jim_thompson5910):

well the teacher will mark it wrong, so just letting the person know

OpenStudy (rajee_sam):

1/100th of a point doesn't matter

jimthompson5910 (jim_thompson5910):

yes the steps are valid, just that last part is off

jimthompson5910 (jim_thompson5910):

well I'm just telling you what a teacher would do

jimthompson5910 (jim_thompson5910):

and what a computer grader would do, ideally you would have partial credit, but it's the answer that counts (most of the time)

OpenStudy (rajee_sam):

@Nerdy_3000 For No. 40 she found the slope just right. But the equation of the line may not have the same y-intercept. Also the question asks for only the slope. So word of caution, do not write unnecessary information and get the whole thing wrong.

OpenStudy (rajee_sam):

@Nerdy_3000 , For No. 42, one line equation you wrote in y=mx + b form. Why did you not do the same for the second one? So focus and do what the right thing is.

OpenStudy (nerdy_3000):

Well I'm rounding to the nearest tenth

jimthompson5910 (jim_thompson5910):

yes, 14.142135623731 to the nearest tenth would be 14.1 and not 14.2

OpenStudy (nerdy_3000):

I didn't see it correctly thanks

jimthompson5910 (jim_thompson5910):

np

OpenStudy (nerdy_3000):

By the way for 45 can you show me what I had to do for that??

jimthompson5910 (jim_thompson5910):

you need to solve \[\large 12^2 + x^2 = (12+8)^2\] for x

jimthompson5910 (jim_thompson5910):

\[\large 12^2 + x^2 = (12+8)^2\] \[\large 12^2 + x^2 = 20^2\] \[\large 144 + x^2 = 400\] I'll let you finish

OpenStudy (nerdy_3000):

Alright you perform Pythagorean Theorem then subtract by144 on the both sides and you get 256 then you find the square root which is 16

jimthompson5910 (jim_thompson5910):

good, x = 16, you got it

OpenStudy (nerdy_3000):

😆 Yay!!! Thanks for the help

jimthompson5910 (jim_thompson5910):

np

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