A need someone to check this and if it is wrong can you help me!! And on 45 as well.http://oi42.tinypic.com/fmuh60.jpg
you got no. 44 right. So no. 45 just similar to that
Thanks!
see attached for what you got right/wrong
why is 44 wrong?
for #45, you need to solve the following for x \[\large 12^2 + x^2 = (12+8)^2\]
@jim_thompson5910 , Why is her 44 wrong?
because \[\large \sqrt{200} \approx 14.142135623731 \approx 14.1\] and NOT 14.2
oh come on!!
her method is absolutely right
well the teacher will mark it wrong, so just letting the person know
1/100th of a point doesn't matter
yes the steps are valid, just that last part is off
well I'm just telling you what a teacher would do
and what a computer grader would do, ideally you would have partial credit, but it's the answer that counts (most of the time)
@Nerdy_3000 For No. 40 she found the slope just right. But the equation of the line may not have the same y-intercept. Also the question asks for only the slope. So word of caution, do not write unnecessary information and get the whole thing wrong.
@Nerdy_3000 , For No. 42, one line equation you wrote in y=mx + b form. Why did you not do the same for the second one? So focus and do what the right thing is.
Well I'm rounding to the nearest tenth
yes, 14.142135623731 to the nearest tenth would be 14.1 and not 14.2
I didn't see it correctly thanks
np
By the way for 45 can you show me what I had to do for that??
you need to solve \[\large 12^2 + x^2 = (12+8)^2\] for x
\[\large 12^2 + x^2 = (12+8)^2\] \[\large 12^2 + x^2 = 20^2\] \[\large 144 + x^2 = 400\] I'll let you finish
Alright you perform Pythagorean Theorem then subtract by144 on the both sides and you get 256 then you find the square root which is 16
good, x = 16, you got it
😆 Yay!!! Thanks for the help
np
Join our real-time social learning platform and learn together with your friends!