Question

Find the value of x.
FG perpendicular to OP, RS perpendicular to OQ, FG=20, RS=24, OP=14

Answer 1

@Hunus
@jim_thompson5910

Answer 2

let r = radius of the circle

Answer 3

by the pythagorean theorem, we can say

(FP)^2 + (OP)^2 = (OF)^2

10^2 + 14^2 = r^2

solve for r and tell me what you get

Answer 4

100 + 196 = 296^2. Now what?

Answer 5

r^2 = 296

so

r = ???

Answer 6

296

Answer 7

no

Answer 8

r^2 is 296, not r

Answer 9

87, 616

Answer 10

don't square it though

Answer 11

how do you undo squaring something

Answer 12

sqrt?

Answer 13

yep

Answer 14

16.9?

Answer 15

you did sqrt(296) right?

Answer 16

Yea

Answer 17

it's close, but not correct

Answer 18

sqrt(296) = 17.2046505340852

round to whatever place you need to

Answer 19

17.2 isn't one of the answers. Only 16.9

Answer 20

but remember, we want x, not r

Answer 21

we use r to get x

Answer 22

the possible answers are: 16.9, 14, 12.3, and 12..

Answer 23

\[\large r = \sqrt{296} \rightarrow r^2 = 296\]

\[\large (OQ)^2 + (RQ)^2 = (OR)^2\]

\[\large (OQ)^2 + (RQ)^2 = r^2\]

\[\large x^2 + 12^2 = 296\]

\[\large x^2 + 144 = 296\]

...
...
...

\[\large x = ???\]

Answer 24

152

Answer 25

12.3

Answer 26

\[\large x^2 = 152\]

so

\[\large x = ???\]

Answer 27

good, x is roughly 12.3

Answer 28

What about this one?

Answer 29

what about it? what do you want to find? and what are you given?

Answer 30

Oh. Lol. Forgot.\
AB is a diameter and AB is perpendicular to CD.

Answer 31

alright so that's all the given info?

Answer 32

I know the angles are all 90 degrees.

Answer 33

what do you need to find exactly?

Answer 34

Find BD for AC= 58 DEGREES

Answer 35

AC is a segment, not an angle

Answer 36

Okay..

Answer 37

so is it ACP or ACB that's 58 degrees

Answer 38

This is exactly what it says.
Find m BD for m AC= 58 degrees.

Answer 39

oh arc AC, gotcha

Answer 40

angle APC = (1/2)*(arc AC + arc BD)

90 = (1/2)*(58 + x)

90*2 = 58 + x

180 = 58 + x

solve for x

Answer 41

122

Answer 42

yep