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Mathematics 6 Online
OpenStudy (anonymous):

In a large bag of candy, each of the 5 colors (red, orange, yellow, blue, and green) occurs with the same probability. You reach in and select 2 candies. Find the probability that both candies are orange.

OpenStudy (anonymous):

So if there are five colors with an equal occurance than the probability of getting orange is 1/5, now given two trials and you want the result, you would multiply the probabilities. This makes sense because it should get more "difficult/improbable" as we want successive trials of the same color. Think, if you wanted a million orange in a row, that should have a tiny probability. SO... \[P(orange twice) = P(orange)^{2}= (\frac{1}{5})^{2}= \frac{1}{25}\]

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