Question

help?!?

Answer 1

what is angle B ?

Answer 2

angle B= 180 - 24
can you find angle ACB knowing A is 16, and B is 156 ?

Answer 3

remember 3 angles of a triangle add up to 180º

Answer 4

if you can find angle ACB, you can use the Law of Sines to find the side BC
\[ \frac{BC}{\sin 16}= \frac{7600}{\sin( ACB)} \]

Answer 5

can you be more specific ?

Answer 6

yes, angle at C is 8º
now use the Law of Sines to find the length of side BC

Answer 7

bc/sin16= 7600/ sin (16)(156)(8)

Answer 8

**im not typing i dont know why its saying that**

that's scary.

what is this
bc/sin16= 7600/ sin (16)(156)(8) ??


\[ \frac{BC}{\sin 16}= \frac{7600}{\sin( 8º)} \]

Answer 9

hah! iknow

Answer 10

no, I was trying to say the angle at C (start at A go to C, then go to B)

the Law of Sines
see http://www.mathsisfun.com/algebra/trig-sine-law.html

uses the ratio of the sin(angle) / side opposite
in this case, we want to know side BC, so we need to know the angle across from BC. we do , it is 16º

we know side AB= 7600, so we want to know the angle opposite that side. it is angle C=8

Answer 11

if you work it through, you can write
\[ \frac{BC}{\sin (16º)}= \frac{7600}{\sin( 8º)} \]

multiply both sides by sin(16).
\[ \frac{BC}{\sin (16º) }\cdot \sin(16º)= \frac{7600}{\sin( 8º)} \cdot \sin(16º)\]

Answer 12

on the left side, sin(16)/sin(16) "cancel" (become 1 so we can ignore)
now get a calculator and figure out BC

Answer 13

what were those 2's they are little º meaning "degrees"

Answer 14

no.

start with
\[ \frac{BC}{\sin (16º) }\cdot \sin(16º)= \frac{7600}{\sin( 8º)} \cdot \sin(16º) \]

Answer 15

only on the left side

you should remember that anything divided by itself is 1
so the left side
\[ \frac{BC}{\sin (16º) }\cdot \sin(16º) = BC \cdot \frac{\sin(16)}{\sin(16)}= BC \cdot 1 = BC \]

Answer 16

you need a calculator to figure out the right side

Answer 17

yes, but the sin(16) is up top

7600*sin(16)/sin(8)

Answer 18

yes. but I think they want to the nearest foot

Answer 19

you can use the Law of Sines to do part (b)

Answer 20

in triangle BCD , what side do you know ?

Answer 21

are you looking at the same picture I am ?
put you finger on B, go to C, down to D, over to B. that triangle.
which of its 3 sides do you know ?

Answer 22

yes, but what did you figure out in part (a) ?

Answer 23

You found the length of side BC in part (a)
BC= 15052.07

Answer 24

oh!

Answer 25

do you know the angle that is opposite to side BC ?

Answer 26

no.. how do i find that?

Answer 27

the angle opposite side BC is the angle that is not B and not C

Answer 28

im sorry but i just dont understand..

Answer 29

what is the *angle* opposite side BC ? you have 3 choices: B , C or D. (and it's not B or C)